Matematika

Pertanyaan

Jika f(x) = x + 2 dan g(x) = 3 X ^ 2 + 4 x + 1 maka (gof) (x) =

2 Jawaban

  • (gof)(x)
    = g(f(x))
    = 3((x+2)²) + 4(x+2) + 1
    = 3(x²+4x+4) +4x +8 +1
    = 3x² + 12x + 12 + 4x + 9
    = 3x² + 16x + 21
  • (gof)(x) = g(fx)
    g(x+2) = 3(x+2)² + 4(x+2) + 1
    = 3(x²+4x+4) + 4(x+2) +1
    = (3x² + 12x+12)+ (4x+8) +1
    = 3x² +16x + 21
    maka, (gof)(x) = 3x² +16x + 21

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