sederhanakanhasil kali bentuk aljabar: 1).4(3a+2) 2). (×+3)(×-2) 3). (2×-1)(×+2y-3)

[tex]1) \\ 4(3a+2) = 12a + 8 \\ \\
2) \\ (x+3)(x-2) = {x}^{2} - 2x + 3x - 6 = {x}^{2} + x - 6 \\ \\
3) \\ (2x-1)(x+2y-3) \\ = 2 {x}^{2} + 4xy - 6x - x - 2y + 3 \\ = 2 {x}^{2} + 4xy - 7x - 2y + 3[/tex]