yolong yang jao matematika nomer 8 dengam metode eliminasi dan subtitusi

X + Y = 600 (X= jumlah koin 500 , Y= jumlah koin 1000)

500x+1000Y= 457.500

Dit: X=...? Y=...?

jwb:

Eliminasi

500x+1000Y= 457.500   |x1|      500X+1000Y= 457.500

X + Y = 600                     |x500|  500X+500Y = 300.000

                                                    ----------------------------- -

                                                           500Y=157.500

                                                                 Y=157.500/500=315

Substitusi

X+Y=600

X=600-315

X=285