diketahui f(x+1)=2x dan (fog)(x+1)=2x*2+4x-2. rumus fungsi g(x) =

f(x+1) = 2x
fog(x+1) = 2x² + 4x - 2, maka

f(g(x+1))
2(g(x+1)) = 2x² + 4x - 2
g(x+1) = x² + 2x - 1
g(x) = (x - 1)² + 2(x - 1) - 1
g(x) = x² - 2x + 1 + 2x - 2 - 1
       = x² - 2

jawab
"dengan cara lain"

f(x+1) = 2x
f(x)= 2(x -1) = 2x - 2

fog(x+1) = 2x² + 4x - 2
2. g(x+1) - 2 = 2x² + 4x - 2
2 { g(x+1) - 1)} = 2 (x² +2x - 1)
g(x+1) - 1 = x² + 2x - 1
g(x+1) = x² + 2x
g(x) = (x-1)² + 2(x-1)
g(x) = x² -2x + 1 + 2x - 2
g(x) = x² - 1