Hasil dari persamaan linear 3 variabel ×+y+z=-1 2×+2y+3z=-2 3×-2y-z=2

(x+y+z =-1) x2 = 2x+2y+2z =-2
(2x+2y+3z =-2)×1 = 2x+2y+3z=-2
=>( 2x+2y+2z=-2) - (2x+2y+3z)=-2
hasilnya -z=0 -> z=0
(2x+2y+3z=-2)×3= 6x+6y+6z=-6
(3x-2y-z=2) x2= 6x-4y-2z=4
(6x+6y+6z=-6)-(6x-4y-2z=4)
10y+8z=-10
10y+8(0)=10
10y =10
y=1
untuk mencari nilai x :
x+y+z=-1
x+1+0=-1
x=-1-1
x=-2
jadi, x=-2 , y=1 , z=0