tentukan penyelesaian sistem persamaan berikut dengan metode substitusi..a.x=y dan x+y=6 b.x=y-10dan x=2y+8 c.x-2y= 2 dan 3y-5x=-24

a) x = y
x + y = 6
y + y = 6
2y = 6
y = 3
x = y = 3
hp = {3,3}

b) x = y - 10
x = 2y + 8
x - 2y = 8
y - 10 - 2y = 8
- y = 8 + 10
y = - 18
x = y - 10
x = - 18 - 10
x = - 28
hp = {-28,-18}

c) x - 2y = 2
x = 2y + 2
3y - 5x = - 24
3y - 5(2y + 2) = - 24
3y - 10y - 10 = - 24
- 7y = - 24 + 10
y = - 14 ÷ - 7
y = 2
x = 2y + 2
x = 2(2) + 2
x = 4 + 2
x = 6
hp = {6,2}