Tentukan persamaan garis lurus melalui titik (1,6) dan (7,4)

y-y1/y2-y1 = x-x1/x2-x1

y-6/4-6 = x-1/7-1
y-6/-2 = x-1/6
6y-36 = -2x+2
6y = -2x + 38
y = -⅓x + 19/3

pers garis
(y - y1) / (y2 - y1) = (x - X1) / (x2 - X1)
(y - 6) / (4 - 6) = (x - 1) / (7 - 1)
(y - 6) / - 2 = (x - 1) / 6
6 (y - 6) = - 2(x - 1)
6y - 36 = - 2x + 2
6y + 2x = 36 + 2
6y + 2x = 38