tolong kerjain ya bsk dikumpul

2) luas selimut= 2×π×r×t
528= 2×22/7×r×12
528= 75,42×r
r= 528÷75,42
r= 7 cm
d= 7×2
d= 14 cm

3)luas permukaan= π×r (r+s)
282,86= 22/7×5 (5+s)
282,86= 15,7×5s
5s= 282,86÷15,7
5s= 18
s= 18-5
s= 13 cm

t²= s²-r²
t²= 13²-5²
t²= 169-25
t²= 144
t= √144
t= 12 cm

4) luas selimut= π×r×s
204,1= 3,14×5×s
204,1= 15,7×s
s= 204,1÷15,7
s= 13 cm

t²= s²-r²
t²= 13²-5²
t²= 169-25
t²= 144
t=√144
t= 12 cm

Volume kerucut= 1/3×π×r²×t
= 1/3×3,14×5²×12
= 314 cm³

5) luas alas= π×r²
120= 3,14×r²
r²= 120÷3,14
r²= 38,21
r= √38,21
r= 6,18 cm

volume= 1/3×π×r²×t
360= 1/3×3,14×6,18²×t
360= 39,99×t
t= 360÷39,99
t= 9 cm