1 1per5 + 3 1per2 : 2 1per6

[tex] \frac{11}{5} + \frac{31}{2} \div \frac{21}{6} \\ \frac{11}{5} + \frac{31}{2} \times \frac{6}{21} \\ \frac{11}{5} + \frac{93}{21} \\ \frac{22}{105} + \frac{93}{105} \\ \frac{115}{105} [/tex]
semoga membantu!