Tentukan himpunan penyelesaian dari

[tex] \frac{ {4}^{x + 2} }{8} = \sqrt{8 ^{x} } \\ {4}^{x + 2} = 8 \sqrt{ {8}^{x} } \\ 8 \sqrt{ {8}^{x}} = {4}^{x + 2} \\ 64 \times {8}^{x} = {4}^{(x + 2) \times 2} \\ {2}^{6} \times ( {2}^{3})^{x} = {4}^{2x + 4} \\ {2}^{6} \times {2}^{3x} = {2}^{4x + 8} \\ {2}^{3x + 6} = {2}^{4x + 8} \\ 3x + 6 = 4x + 8 \\ 3x - 4x = 8 - 6 \\ - x = 2 \\ x = - 2[/tex]
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