Matematika

Pertanyaan

Soal cerita Aljabar kelas 7 SMP semester ganjil
Soal cerita Aljabar kelas 7 SMP semester ganjil

2 Jawaban

  • 3. Tabungan Ibu = tabungan anita
    100.000 = 2x + 30.000
    100.000-30.000 = 2x
    70.000 = 2x
    x = 35.000

    100.000 = 2×35.000 + 30.000
    100.000 = 70.000 + 30.000
    100.000 = 100.000
  • 1. misalkan
    x = lebar
    y = panjang
    y = x + 3
    diketahui keliling = 66, maka
    K = 2x + 2y
    66 = 2x + 2(x+3)
    66 = 2x + 2x + 6
    66 - 6 = 4x
    4x = 60
    x = 15

    y = x + 3
    y = 15 + 3
    y = 18
    jadi panjang = 18 
    dan lebar = 15

    ==============================

    utk mi instan ada 30 dus, 1 dus = 144 bungkus, dan 1 bungkus = 900, maka
    900 . 144 . 30
    = 3.888.000
    utk minyak goreng ada 50 liter, 1 liter = 5400, maka
    5400 . 50
    = 270.000
    harganya
    3.888.000 + 270.000 = 4.158.000

    =============================================

    Tabungan Ibu = 100.000
    tabungan ibu = 2 × tabungan Anita + 30.000
    100.000 = 2 × TA + 30.000
    100.000 - 30.000 = 2TA
    70.000 = 2 TA
    TA = 70.000 / 2
    TA = 35.000
    jadi tabungan Anita = 35.000

    ===============================

    x : bilangan asli
    karena 33 = jumlah bil. asli berurutan 
    maka
    x + (x+1) + (x+2) = 33
    3x + 3 = 33
    3x - 30 = 0

    =================================

    p = (3x - 4)
    le = (x + 1)

    (a). K = 2p + 2le
          K = 2(3x - 4) + 2(x + 1)
          K = 6x - 8 + 2x + 2
          K = 8x - 6

    (b). untuk x = 12, maka
    K = 8(12) - 6
    K = 90