barisan aritmatika u4=17 dan u41=165 ditanyakan u7=?

U4=a+3b=17
U41=a+40b=165_
-37b= -148
b = 4

U4=a+3b=17
U4=a+3(4)=17
U4=a+12=17
a=17-12
a=5

U7=a+6b
U7=5+6(4)
U7=5+24
U7=29