no. 8 logaritma. mohon bantuannya

[tex]$\begin{align}^{\sqrt{2\sqrt2}}\log x&=\frac1{1-\log5}\\^{\left(2\sqrt2\right)^{\textstyle\frac12}}\log x&=\frac1{\log10-\log5}\\\frac1{\frac12}\times{^{\sqrt8}}\log x&=\frac1{\log\frac{10}5}\\2\times{^\textstyle8^{\textstyle\frac12}}\log x&=\frac1{\log2}\\2\times\frac1{\frac12}\times{^8}\log x&=\frac1{\log2}\\4\times{^8}\log x&=\frac1{\log2}\\^8\log x&=\frac1{4\times\log2}\\^8\log x&=\frac1{\log2^4}\\^8\log x&={^{2^4}}\log10\\^{2^3}\log x&={^{2^4}}\log10\\\frac{^2\log x}3&=\frac{^2\log10}4\end[/tex]


Lanjutan


[tex]$\begin{align}\frac43\times{^2}\log x&={^2}\log10\\{^2}\log x^{\textxstyle\frac43}&={^2}\log10\\x^{\textstyle\frac43}&=10\\x&=\sqrt[4]{10^3}\\x&=\boxed{\sqrt[4]{1.000}}\ \bold{(E.)}\end[/tex]