mohon untuk di jawab#trimakasih

[tex]^ {\frac{1}{3} }log( x^{2} + x - 3) = -2 \\ \\ x^{2} + x - 3 = ( \frac{1}{3})^{-2} \\ x^{2} + x - 3 = 9 \\ x^{2} + x - 3 - 9 = 0 \\ x^{2} + x - 12 = 0 \\ (x + 4)(x - 3) = 0 \\ \\ x + 4 = 0 \\ x = -4 \\ \\ dan \\ \\ x - 3 = 0 \\ x = 3 \\ \\ [/tex]

HP = {-4, 3}

Jawaban C