(^2log 8)^2/^3log 27

(²log 8)²/³log 27
=(²log 2³)²/³log 3³
=(3 ²log2)²/3 ³log 3
=3²/3
=9/3
=3

(^2log8)^2/ ^3log27=
(^2log2^3)^2 /^3log3^3
(3)^2/3
=9/3=3
ket:
^aloga^c= c
jadi ^2log2^3= 3 dan ^3log3^3= 3