Matematika

Pertanyaan

tolong krjkan skrang y
tolong krjkan skrang y

1 Jawaban

  • Misal fluin = x dan fluon = y

    Aspirin. = 2x + y > 12
    Bikarbonat = 5x + 8y > 74
    Kodein = x + 6y > 24

    2x + y > 12 (kali 6) → 12x+6y > 72
    x + 6y >24 (kali 1) → x + 6y > 24
    ____________ -
    11x > 48 → x>48/11

    Substitusi nilai x>48/11 ke salah satu persamaan (sy pakai yg aspirin)
    2x+y >12
    2.48/11 + y > 12
    96/11 + y > 12 → y > 36/11

    Biaya
    Fluin (x) = 2x+5x+x = 8x.500 = 8(48/11) x 500 = 17,454

    Fluon = y+8y+6y = 15y.600 = 15(36/11).600 = 29.454

    Fluin + fluon = 17.454+29.454 = 46.909 rb


    Sorry klo salah
    *i did my best