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waalaikumussalam ._.

1.
Lo = 6 meter = 600 cm
∆T = 35°C
α = 1,2×10⁻⁵/°C

ditanyakan :
∆L = .....?
Lt = ......?

∆L = α . Lo . ∆T
∆L = 1,2×10⁻⁵ . 6×10² . 35
∆L = 252×10-³
∆L = 0,252 cm

L = Lo (1 + α . ∆T)
L = 600 (1 + 1,2×10⁻⁵ . 35)
L = 600 ( 1.00042 )
L = 600,252 cm

2.
p = 50 cm
l = 40 cm
Ao = p.l = 2×10³ cm²
∆T = 125°C
β = 1,2×10⁻⁵/°C

ditanyakan :
∆A = ... ?
At = ..... ?

∆A = β . Ao . ∆T
∆A = 1,2×10⁻⁵ . 2×10³ . 125
∆A = 3×10²×10⁻⁵×10³
∆A = 3 cm²

At = ∆A + Ao
At = 3 cm² + 2000 cm²
At = 2003 cm²
atau
At = Ao (1 + β . ∆T)
At = 2000 (1 + 1,2×10⁻⁵ . 125)
At = 2003 cm²


cmiiw