Matematika

Pertanyaan

Tentukan penyelesaian dari setiap sistem berikut dengan metode eliminasi!
a.{4s-2t-18=0
{-3s+4t+26=0
b.{6m+2n+11=0
{-4m-3n=19

1 Jawaban

  • a) 4s - 2t = 18 |×2
    - 3s + 4t = - 26
    8s - 4t = 36
    - 3s + 4t = - 26
    ----------------------(+)
    5s = 10
    s = 2

    4s - 2t = 18 |×3
    - 3s + 4t = - 26 |×4
    12s - 6t = 54
    - 12s + 16t = - 104
    --------------------------(+)
    10t = - 50
    t = - 10

    hp = {2, -10}

    b) 6m + 2n = - 11 |×2
    - 4m - 3n = 19 |×3
    12m + 4n = - 22
    - 12m - 9n = 57
    -----------------------(+)
    - 5n = 35
    n = - 7

    6m + 2n = - 11 |×3
    - 4m - 3n = 19 |×2
    18m + 6n = - 33
    - 8m - 6n = 38
    -----------------------(+)
    10m = 5
    m = ½

    hp = {½ , - 7}

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