jika f fungsi yg memenuhi persamaan(1)=4 dan f(x+1)=2f(x).tentukan lah f(2014)

jawab

f(1)= 4
f(x+1) = 2. f(x)
f(1+1) = 2. f(1)
f(2)= 2. f(1)
f(2)= 2(4)= 8

f(3) = 2. f(2) = 16

4 , 8, 16
a = 4
r = 2

u 2014  = a rⁿ⁻¹
U2014 =  4. 2²⁰¹³
u 2014 = 2². 2²⁰¹³
U2014 = 2²⁰¹⁵

f(2014) = 2²⁰¹⁵