Matematika

Pertanyaan

pada sistem persamaan 2x-3y=2 dan 3x=10+y tentukan nilai xpangkat3 -ypangkat3

2 Jawaban

  • Materi : SPLDV

    2x - 3y = 2 ........ ×1
    3x - y = 10 ......... ×3
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    2x - 3y = 2
    9x - 3y = 30
    ◆◆◆◆◆◆◆◆◆◆◆◆◆[-]
    -7x = -28
    x = 4

    2x - 3y = 2
    2(4) - 3y = 2
    8 - 3y = 2
    -3y = 2 - 8
    -3y = -6
    y = 2

    Hp = { 4 , 2 }

    Jadi :
    》x^3 - y^3
    》4^3 - 2^3
    》64 - 8
    》56
  • 2x _ 3y = 2. x 3
    3x _ y = 10. x 2

    6x _ 9y = 6
    6x _ 2y = 20
    __________ _
    _7y = _ 14
    y = _ 14/_7
    y = 2

    2x _ 3y = 2
    2x _ ( 3 x 2) = 2
    2x = 2 + 6
    2x = 10
    x = 10/2
    x = 5

    dit : x^3 dan y^4
    x^3 = 5x5x5 = 125
    y^3 = 2x2x2 = 8

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