16,17,18,19 tolong yaa

16) Keliling alas = 132 cm
2 π r = 132
π r = 66
22/7 .r = 66
r = 66× 7/22
r = 21 cm
luas penutup dan alas tabung = 2 (luas lingkaran) =
= 2 ( π r^2)
= 2 ( 22/7.21^2)
= 2.794 cm^2
luas selimut = Keliling alas × tinggi
= 132 × 9
= 1.188 cm^2
luas permukaan = 2.794 + 1.188
= 3.982 cm^2
17)volume bak mandj = π.r^2.t
22/7 (48)^2.80 : 22/7 (8)^2.20
(48)^2.4 : 8^2
(6.8.6.8).4 : 8.8
36.4 : 1
144 : 1
Jadi ada 144 kali
18) n(S) = 2^3×6 = 48
19) E = { 3, 5 } ==> n(E) = 2
P(E) = 2/6 = 1/3