Matematika

Pertanyaan

F(-1)=3 f(2)=-6 tentukan bentuk fungsi

1 Jawaban

  • f ( -1) = ax + b = 3
    = -a+ b = 3
    f (2) = ax + b= -6
    = 2a + b = -6
    -a +b = 3
    2a + b = -6 _
    _________
    - 3a= 9
    a = -3
    - a+ b = 3
    -(-3) + b = 3
    3+ b = 3
    b = 3 - 3
    = 0
    f(x) = ax + b
    = -3x + 0
    = -3x

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