tolong ya 1-4 tolong di jawab

1) 2x + 3y - 6 = 0
3y = - 2x + 6
m = - ⅔
sejajar m1 = m2 = - ⅔
pers garis :
y - y1 = m ( x - x1)
y - 3 = - ⅔ ( x - 0)
y = - ⅔ x + 3 ( dikali 3)
3y = - 2x + 9
3y + 2x = 9

2) 6x = - 2y - 4
2y = - 6x - 4
m = - 6/2
m = - 3
syarat tegak lurus
m1 . m2 = - 1
- 3 . m2 = - 1
m2 = ⅓
pers garis :
y - y1 = m ( x - x1)
y + 3 = ⅓ ( x - 3)
y = ⅓ x - 1 - 3
y = ⅓x - 4 ( dikalikan 3)
3y = x - 12
3y - x + 12 = 0

3) mg = ( y2 - y1) / ( x2 - x1)
mg = (2 - 0) / ( 3 - 0)
mg = 2/3
sejajar m1 = m2 = ⅔
pers garis
y - y1 = m ( x - x1)
y - 1 = ⅔ ( x + 2)
y = ⅔ x + 4/3 + 1 ( dikali 3)
3y = 2x + 4 + 3
3y = 2x + 7
3y - 2x = 7

4) 5x = 2y - 7
m = 2/5
syarat tegak lurus
m1 . m2 = - 1
2/5 . m2 = - 1
m2 = - 1 ÷ 2/5
m2 = - 5/2
pers garis
y - y1 = m ( x - x1)
y - 5 = - 5/2 ( x - 3)
y = - 5/2 x + 15/2 + 5 (dikalikan 2)
2y = - 5x + 15 + 5
2y + 5x = 20