log(2x-1)-log(x-3)=log 7 mencari nilai X ?

[tex] log(2x - 1) - log(x - 3) = log(7) \\ log( \frac{2x - 1}{x - 3} ) = log(7) \\ \frac{2x - 1}{x - 3} = 7 \\ 2x - 1 = 7x - 21 \\ - 5x = - 20 \\ x = 4[/tex]

log(2x-1) - log(x-3) = log 7
log( (2x - 1) / (x - 3) ) = log 7
⇔ (2x - 1) / (x - 3) = 7
⇔ 2x - 1 = 7(x - 3)
⇔ 2x - 1 - 7x + 21 = 0
⇔ -5x + 20 = 0
⇔ x = 4