Matematika

Pertanyaan

Aljabar :
4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] =

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1 Jawaban

  • 4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] 
    = 4x² - {3x-(x²-x-4)}+[x²-(x-3)] 
    = 4x² - (-x²+4x+4)+(x²-x+3)
    = 4x² + x² - 4x - 4 +(x²-x+3)
    = 5x² - 4x - 4 +(x²-x+3)
    = 5x² + x² - 4x - x - 4 + 3
    = 6x² - 5x - 1

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