Aljabar : 4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] = Tolong dijawab

4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] 
= 4x² - {3x-(x²-x-4)}+[x²-(x-3)] 
= 4x² - (-x²+4x+4)+(x²-x+3)
= 4x² + x² - 4x - 4 +(x²-x+3)
= 5x² - 4x - 4 +(x²-x+3)
= 5x² + x² - 4x - x - 4 + 3
= 6x² - 5x - 1