Aljabar : 4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] = Tolong dijawab
Matematika
AnsellRJ
Pertanyaan
Aljabar :
4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] =
Tolong dijawab
4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}] =
Tolong dijawab
1 Jawaban
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1. Jawaban pendekaredu
4x²-{3x-(x²-(4+x))}+[x²-{x+(-3)}]
= 4x² - {3x-(x²-x-4)}+[x²-(x-3)]
= 4x² - (-x²+4x+4)+(x²-x+3)
= 4x² + x² - 4x - 4 +(x²-x+3)
= 5x² - 4x - 4 +(x²-x+3)
= 5x² + x² - 4x - x - 4 + 3
= 6x² - 5x - 1