tentukan himpunan penyelesaiyan SPDLV dengan netode eliminasi a. 3x+2y=5 dan 2x+y=1 b. 2x+4y=4 dan 3x+2y=6

[tex]a. \\ 3x + 2y = 5 \: \: | \times 2| \\ \frac{2x + y = 1 \: \: \: \: | \times 3| }{} - \\ 6x +4y = 10 \\ \frac{6x + 3y = 3}{y = 7} - \\ \\ 3x + 2y = 5 \\ \frac{2x + y = 1 \: \: \: \: | \times 2| }{} - \\ 3x + 2y = 5 \\ \frac{4x + 2y = 2}{ - x = 3 } - \\ x = - 3 \\ \\ b. \\ 2x + 4y = 4 \: \: \: \: | \times 3| \\ \frac{3x + 2y = 6 \: \: \: \: | \times 2| }{} - \\ 6x + 12y = 12 \\ \frac{6x + 4y = 12}{8y = 0} \\ y = 0 \\ \\ 2x + 4y = 4 \\ \frac{3x + 2y = 6 \: \: \: | \times 2| }{} - \\ 2x + 4y = 4 \\ \frac{6x + 4y = 12}{ - 4x = - 8} - \\ x = 2[/tex]

smogaa membantuu:D

a. 3x + 2y = 5 ( × 2 ) = 6x + 4y = 10
2x + y = 1 (× 3 ) = 6x + 3y = 3
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y = 7

3x + 2y = 5 ( × 1 ) = 3x + 2y = 5
2x + y = 1 ( × 2 ) = 4x + 2y = 2
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-1 x = 3
x = -1 : 3
x = -3

yang B nya sama cara nya kaya gitu