1. √75 - 2√27 + 4√12=.... 2. (√6 - 2√2 ) (2√6 + √2 ) =... dibantu yahh
Matematika
infaisal
Pertanyaan
1. √75 - 2√27 + 4√12=....
2. (√6 - 2√2 ) (2√6 + √2 ) =...
dibantu yahh
2. (√6 - 2√2 ) (2√6 + √2 ) =...
dibantu yahh
1 Jawaban
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1. Jawaban ekamiaww
1. √75 - 2√27 + 4√12
= 5√3 - 2.3√3 + 4.2√3
= 5√3 - 6√3 + 8√3
= 7√3
2. (√6 - 2√2 ) (2√6 + √2 )
= 2.6 + √12 - 4√12 - 2.2
= 12 + √12 - 4√12 - 4
= 8 - 3√12
= 8 - 3.2√3
= 8 - 6√3